Tim Van Wassenhove home

Imagine that you have a schema where you store all the times a player needed to complete a parcours. A possible schema could be (postgresql)

CREATE TABLE laptimes (
lap_id SERIAL NOT NULL,
player_id INT NOT NULL,
laptime INT NOT NULL,
PRIMARY KEY (lap_id)
);

INSERT INTO laptimes (player_id, laptime) VALUES (1, 250);
INSERT INTO laptimes (player_id, laptime) VALUES (1, 450);
INSERT INTO laptimes (player_id, laptime) VALUES (1, 350);
INSERT INTO laptimes (player_id, laptime) VALUES (1, 300);
INSERT INTO laptimes (player_id, laptime) VALUES (1, 327);

INSERT INTO laptimes (player_id, laptime) VALUES (2, 327);
INSERT INTO laptimes (player_id, laptime) VALUES (2, 249);
INSERT INTO laptimes (player_id, laptime) VALUES (2, 123);
INSERT INTO laptimes (player_id, laptime) VALUES (2, 489);
INSERT INTO laptimes (player_id, laptime) VALUES (2, 158);

INSERT INTO laptimes (player_id, laptime) VALUES (3, 158);
INSERT INTO laptimes (player_id, laptime) VALUES (3, 120);
INSERT INTO laptimes (player_id, laptime) VALUES (3, 190);

INSERT INTO laptimes (player_id, laptime) VALUES (4, 600);

Now imagine that you want to display the best 3 results for each player. Here’s how

SELECT *
FROM laptimes AS l1
WHERE lap_id IN (
SELECT lap_id
FROM laptimes AS l2
WHERE l1.player\_id = l2.player\_id
ORDER BY laptime ASC
LIMIT 3
)
ORDER BY player_id ASC, laptime ASC;