Tim Van Wassenhove home

If you read this you’re probably gonna think: What a moron! Anyway, i’m sharing this in the hope that i’ll be the last to undergo the following. In order to test my custom UITypeEditor i did the following

  1. Create a UserControl
  2. Add a property to the control
  3. Add an Editor attribute to the property
  4. Build
  5. Drag a UserControl on the designer form
  6. Test via Visual Studio’s Property Window if the UITypeEditor works as expected
  7. Everytime i changed some code: Restart Visual Studio, load the project and repeat 6.

A tedious task to say the least. Yesterday i figured out that i could drag a PropertyGrid on the designer form, and set it’s SelectedObject property to a class with a property that uses the custom UITypeEditor; Instead of having to reload visual studio i can simply start a debug session, and click on the property in the PropertyGrid. Now it’s a breeze to develop custom UITypeEditors.

private void Form1_Load(object sender, EventArgs e)
{
	// display an instance of PersonEntry,
	// a class with a property that should use the custom UITypeEditor i want to test
	this.propertyGrid1.SelectedObject = new PersonEntry(new Person("Tim", "Van Wassenhove"));
}

public class PersonEntry
{
	...

	// instruct the PropertyGrid to use my custom PersonUITypeEditor
	[Editor(typeof(PersonUITypeEditor), typeof(UITypeEditor))]
	public Person Person
	{
		get { return this.person; }
		set { this.person = value; }
	}
}

public class PersonUITypeEditor : UITypeEditor
{
	public override UITypeEditorEditStyle GetEditStyle(ITypeDescriptorContext context)
	{
		return UITypeEditorEditStyle.Modal;
	}

	public override object EditValue(ITypeDescriptorContext context, IServiceProvider provider, object value)
	{
		Person person = value as Person;

		IWindowsFormsEditorService svc = context.GetService(typeof(IWindowsFormsEditorService)) as IWindowsFormsEditorService;
		if (svc != null)
		{
			using (PersonEditorForm personEditorForm = new PersonEditorForm(person))
			{
				if (svc.ShowDialog(personEditorForm) == DialogResult.OK)
				{
					return personEditorForm.Person;
				}
			}
		}

		return value;
	}
}